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محاكاة: Capacitor & Dielectric Lab

عن هذه المحاكاة

محاكاة: Capacitor & Dielectric Lab is a 3D electrostatics simulation where students manipulate the geometry and dielectric material of a parallel-plate capacitor. Two metallic plates are wired to an adjustable DC battery while red (+) and blue (−) surface charges accumulate on the inner faces and cyan vector arrows display the uniform electric field E = V / d. Students can drag the top plate up or down to change separation d, change plate area A, and drag an amber dielectric slab horizontally into the gap. Inside the slab, molecular dipole dumbbells visibly rotate to align with the field, illustrating why a dielectric increases capacitance according to C = kappa epsilon_0 A / d.

ما الذي يمكن للطلاب استكشافه

  • محاكاة: Drag the top plate downward to halve the Plate separation d and verify that Capacitance C, Stored charge Q, and Electric field E all double.
  • محاكاة: Drag the amber dielectric slab from 0% to 100% insertion and watch extra + and - charges flow from the battery onto the plates as Capacitance multiplies by kappa.
  • محاكاة: Zoom in with the Gap & Dipoles camera view and vary Battery voltage V to watch the red/blue molecular dipoles inside the dielectric rotate into alignment.
  • محاكاة: Increase Plate area A from 100 cm² to 400 cm² and check that Capacitance C and Stored energy U quadruple.
  • محاكاة: Compare Stored energy U = 1/2 C V² at 6 V and 12 V to verify that doubling voltage quadruples stored electrostatic energy.

أهداف التعلّم

  1. 1محاكاة: Calculate parallel-plate capacitance from plate geometry and permittivity using C = kappa epsilon_0 A / d.
  2. 2محاكاة: Explain at the molecular level how dipole polarization inside a dielectric weakens the net internal field and increases capacitance.
  3. 3محاكاة: Predict how changing voltage V, plate area A, or separation d affects stored charge Q = C V and stored energy U = 1/2 C V².
  4. 4محاكاة: Relate the uniform electric field strength between the plates to voltage and gap distance via E = V / d.

أسئلة يطرحها المعلمون

محاكاة: Why does inserting a dielectric slab increase a capacitor's capacitance?

محاكاة: The external electric field polarizes molecules inside the insulating dielectric, aligning their positive ends toward the negative plate and negative ends toward the positive plate. This creates a small opposing electric field inside the slab, allowing the battery to push kappa times as much charge onto the plates at the same voltage.

محاكاة: How does plate separation d affect capacitance and electric field?

محاكاة: Capacitance C = kappa epsilon_0 A / d and electric field E = V / d are both inversely proportional to separation d. Bringing the plates closer together strengthens the attraction between opposite charges on the two plates, increasing C, Q, U, and E.

محاكاة: Why does stored energy U grow with the square of voltage (V²)?

محاكاة: Because stored charge Q = C V is itself proportional to voltage V, each additional unit of charge must be pushed onto the plate against an increasingly higher potential difference, giving U = 1/2 Q V = 1/2 C V².

محاكاة: Does current flow through the gap between the capacitor plates?

محاكاة: No conduction current crosses the insulating air or dielectric gap. Instead, charging current flows through the external battery wires until the voltage across the plates equals the battery voltage.

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